newbie: retrieve poly-selection from link

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 09/06/2004 at 07:58, xxxxxxxx wrote:

User Information:
Cinema 4D Version:   8.100
Platform:   Windows ;
Language(s) :     C++ ;

---------
Hi all,

im just starting with my first plugin and i have a problem i cant seem to solve on my own.

I wrote a tag plugin, which can be attached as an expression and which has a link field that accepts polygon selections.

My question now is, how do i access the polygon selection in my functions?

i tried it like this:

BaseList2D* polySelection = tag->GetData().GetLink(1001,doc);

but i still dont know how to access the polys
and besides, cinema crashes when i clear the link field..

thanks in advance,
devel

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 09/06/2004 at 15:20, xxxxxxxx wrote:

You should cast the return object into a SelectionTag, you should then check that its non NULL, this will avoid the crashes.
Use the SelectionTag to get the selection

    
    
    
    
    SelectionTag *polySelection = static_cast<SelectionTag*>(tag->GetData().GetLink(1001,doc));
    
    
    
    
    if(!polySelection) return FALSE;
    
    
    
    
     
    
    
    
    
    BaseSelect *selectedpolies = polySelection->GetBaseSelect();
    
    
    
    
     
    
    
    
    
    // Unefficiently check for selected polies
    
    
    
    
    for(LONG i=0; i < selectedpolies->GetCount();i++)
    
    
    
    
    {
    
    
    
    
      if(selectedpolies->IsSelected(i))
    
    
    
    
      {
    
    
    
    
        GePrint("Polygon Selected :" + LongToString(i));
    
    
    
    
      }
    
    
    
    
    }

Look in the docs BaseSelect::IsSelected for an efficient algorithm

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 09/06/2004 at 16:32, xxxxxxxx wrote:

alright, that does it!

thanks for your help,
devel