Set Sweep Spline Points?
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THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 11/07/2012 at 23:48, xxxxxxxx wrote:
Having a hard time with this spline stuff, how do I get this to work on a tag?
def main() :
obj = op.GetObject()
sweepSpline = obj[c4d.SWEEPOBJECT_SPLINESCALE]
s1XPos = some changing value
sweepSpline.SetKnot(index=0, vPos= c4d.Vector(s1XPos, 0, 0)) -
THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 12/07/2012 at 02:56, xxxxxxxx wrote:
One would think one should only reset the spline with the changed point like:
obj[c4d.SWEEPOBJECT_SPLINESCALE] = sweepSpline
at the end of the code, but that gives a broken result......
I'd be happy to see how to as well.....
Cheers
Lennart -
THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 12/07/2012 at 09:05, xxxxxxxx wrote:
This seems to work like I'd expect it to work.
What do you think is broken about this code Lennart?#This example sets the spline GUI to 3 points with some tangent settings #This only works in R13++ import c4d def main() : obj = op.GetObject() sweepSpline = obj[c4d.SWEEPOBJECT_SPLINESCALE] sweepSpline.MakeLinearSplineLinear(3) sweepSpline.SetKnot(index=0, vPos=c4d.Vector(0, 0, 0),vTangentRight=c4d.Vector(0,.2,0)) sweepSpline.SetKnot(index=1, vPos=c4d.Vector(.5, .5, 0),vTangentLeft= c4d.Vector(0,.2,0),vTangentRight=c4d.Vector(0,.2,0)) sweepSpline.SetKnot(index=2, vPos=c4d.Vector(1, 1, 0),vTangentLeft= c4d.Vector(-.2,-.4,0)) obj[c4d.SWEEPOBJECT_SPLINESCALE]=sweepSpline
-ScottA
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THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 12/07/2012 at 09:12, xxxxxxxx wrote:
Scott, your code works fine if you are setting the points in the spline at predetermined values, and also restricting the change of any of these values. But what I was looking for was being able to adjust the values of the position of index(1) XPos for example with values that may change over time.
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THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 12/07/2012 at 09:38, xxxxxxxx wrote:
Originally posted by xxxxxxxx
what I was looking for was being able to adjust the values of the position of index(1) XPos for example with values that may change over time.
Maybe I'm being thick headed and not understanding what you want to do.
But it sounds like you just simply need to create variables for the knot's values and put those variables inside of the SetKnot() parameters instead of the hard coded values I used.
Then use those variables to check for certain conditions to change the knot's values.A tag will always execute the code inside of it.
So if you wanted to be able manually move the knot & also move the knot automatically when a condition happens. You'll have to set up some kind of mixing, or switching condition in the code for that.Everything seems to work as expected to me.
But like I said. Maybe I'm misunderstanding what you're trying to achieve.-ScottA
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THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 12/07/2012 at 09:41, xxxxxxxx wrote:
Scott, it works, I don't have the test I did yesterday, so I can't tell as why it failed.
Cheers
Lennart -
THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 12/07/2012 at 09:54, xxxxxxxx wrote:
^OK.
Just wondered if I was missing something.-ScottA
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THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED
On 13/07/2012 at 02:31, xxxxxxxx wrote:
Im sorry Scott, your code does indeed achieve what I was asking for, I just didn't take the time to test it or actually work through it. Thank you.