Thanks!

-b

Alternatively these examples are also included in the Python SDK documentation archive, downloadable here[URL-REMOVED]. Usually we mention example changes in the changelog as well.

[URL-REMOVED] @maxon: This section contained a non-resolving link which has been removed.

Oh, those examples will come in handy. Thanks!
I guess its time to clone that repo and start watching it for changes

-b

Hi,

darby's explanation is correct.
In our Python examples we also have a few scripts demonstrating the Substance API. Especially the substance_iterateGraphInputOutput comes pretty close to your application.

Thats a nice alternative. Thanks.

-b

Alternatively, you might consider storing the elements of the returned tuple in separate variables which makes things a little easier to read at a glance:

  
...
  
    lastOutput = None
  
    while True:
        output, uid, type, name, bmp = c4d.modules.substance.GetSubstanceOutput(assets[0], subGraph[0], False, lastOutput)
  
        lastOutput = output
  
        if name in model:
            channels[name] = (output, uid, type, name, bmp) #Or whatever combination of data you're interested in
  
        if output == None:
            break
  
...

And if you wanted a reason to use output outside of the loop you could do this:

lastOutput = None
output = True
  
while output:
        output, uid, type, name, bmp = c4d.modules.substance.GetSubstanceOutput(assets[0], subGraph[0], False, lastOutput)
  
        lastOutput = output
  
        if name in model:
            channels[name] = (output, uid, type, name, bmp) #Or whatever combination of data you're interested in

But it's basically the same as keeping your break statement and removing output from outside the loop.

Ah! Now i understand. Thanks alot.

-b

That error probably occurs on the second time through the loop if you didn't change this line:

lastOutput = output

to:

lastOutput = output[0]

The return from GetSubstanceOutput() is a tuple and you want to set lastOutput to the first element of the tuple (the PyCObject).

You will need to initialize lastOutput outside of the loop but I'd remove output from outside of the loop.  There's really no reason for it to be there.  It receives a value immediately after entering the loop.

Thanks. Setting lastOutput to None outside the loop gives this error:

TypeError: argument 4 must be PyCObject, not tuple

Output is outside the loop only because its like this in the c++ docs Thanks.

-b

The documentation seems to indicate that passing 'None' for the prevObject attribute will get the first output.

So:

lastOuput = None

Should do it in theory. You also shouldn't need to initiate 'output' before the loop.

Also, it looks like the line:

lastOutput = output

Is setting lastOutput to a tuple when the GetSubstanceOutput() method is expecting a PyCObject.  I suspect this may need to be:

lastOutput = output[0]